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# Bit Counting in Golang | Discover ways to Grasp Software program Engineering, DevOps and Cloud

## The problem#

Write a operate that takes an integer as enter, and returns the variety of bits which are equal to at least one within the binary illustration of that quantity. You’ll be able to assure that enter is non-negative.

Instance: The binary illustration of `1234` is `10011010010`, so the operate ought to return `5` on this case

Possibility 1:

``````package deal answer
import "math/bits"
func CountBits(n uint) int {
return bits.OnesCount(n)
}
``````

Possibility 2:

``````package deal answer
import "math/bits"
var CountBits = bits.OnesCount
``````

Possibility 3:

``````package deal answer
func CountBits(n uint) int {
var res int = 0
for (n>0) {
if (n & 1 == 1) {
res = res + 1
}
n = n >> 1
}
return res
}
``````

## Take a look at circumstances to validate our answer#

``````package deal solution_test
import (
. "github.com/onsi/ginkgo"
. "github.com/onsi/gomega"
)
var _ = Describe("CountBits()", func() {
It("fundamental assessments", func() {
Count on(CountBits(0)).To(Equal(0))
Count on(CountBits(4)).To(Equal(1))
Count on(CountBits(7)).To(Equal(3))
Count on(CountBits(9)).To(Equal(2))
Count on(CountBits(10)).To(Equal(2))
})
})
``````
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