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Calculate Powers of two in Python


The problem

Full the operate that takes a non-negative integer n as enter, and returns an inventory of all of the powers of two with the exponent starting from 0 to n (inclusive).

Examples

n = 0  ==> [1]        # [2^0]
n = 1  ==> [1, 2]     # [2^0, 2^1]
n = 2  ==> [1, 2, 4]  # [2^0, 2^1, 2^2]

The answer in Python code

Choice 1:

def powers_of_two(n):
    out = []
    for i in vary(n+1):
        out.append(2**i)
    return out

Choice 2:

def powers_of_two(n):
    return [2**i for i in range(n+1)]

Choice 3:

def powers_of_two(n):
    return [1<<x for x in range(n + 1)]

Check circumstances to validate our resolution

import check
from resolution import powers_of_two

@check.describe("Fastened Exams")
def fixed_tests():
    @check.it('Fundamental Check Instances')
    def basic_test_cases():
        check.assert_equals(powers_of_two(0), [1])
        check.assert_equals(powers_of_two(1), [1, 2])
        check.assert_equals(powers_of_two(4), [1, 2, 4, 8, 16])
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