The problem
Given a string, it’s important to return a string during which every character (case-sensitive) is repeated as soon as.
double_char("String") ==> "SSttrriinngg"
double_char("Hi there World") ==> "HHeelllloo WWoorrlldd"
double_char("1234!_ ") ==> "11223344!!__ "
The answer in Python code
This will simply be achieved by looping by means of every character and appending it to a listing, which we then be part of and return on the finish:
def double_char(s):
out = []
for i in s:
out.append(i+""+i)
return "".be part of(out)
Nonetheless, we may simplify this right down to a single record comprehension:
def double_char(s):
return "".be part of([i+''+i for i in s])
Or go one step additional:
def double_char(s):
return ''.be part of(c * 2 for c in s)
Take a look at instances to validate our resolution
check.assert_equals(double_char("String"),"SSttrriinngg")
check.assert_equals(double_char("Hi there World"),"HHeelllloo WWoorrlldd")
check.assert_equals(double_char("1234!_ "),"11223344!!__ ")
