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# How you can Discover the Squares in Java

## The problem#

Full the perform that takes an odd integer (`0 < n < 1000000`) which is the distinction between two consecutive excellent squares, and return these squares as a string within the format `"bigger-smaller"`.

Examples

``````9  -->  "25-16"
5  -->  "9-4"
7  -->  "16-9"
``````

## The answer in Java code#

Possibility 1:

``````public class Answer {
public static String findSquares(last int n) {
last lengthy a = (n + 1) / 2;
last lengthy b = a - 1;
return String.format("%d-%d", a * a, b * b);
}
}
``````

Possibility 2:

``````interface Answer {
static String findSquares(lengthy n) {
return (n /= 2) * n + 2 * n + 1 + "-" + n * n;
}
}
``````

Possibility 3:

``````public class Answer{
public static String findSquares(int n){
lengthy n1 = n/2;
lengthy n2 = n1+1;
return String.valueOf(n2*n2)+"-"+ String.valueOf(n1*n1);
}
}
``````

## Check circumstances to validate our answer#

``````import org.junit.Check;
import static org.junit.Assert.assertEquals;
import org.junit.runners.JUnit4;

public class SolutionTest {
@Check
public void testBasicNumbers() {
}
@Check
public void testSmallerNumbers() {
}
@Check
public void testBiggerNumbers() {
}
}
``````
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