How you can Discover the Squares in Java

The problem

Full the perform that takes an odd integer (0 < n < 1000000) which is the distinction between two consecutive excellent squares, and return these squares as a string within the format "bigger-smaller".

Examples

9  -->  "25-16"
5  -->  "9-4"
7  -->  "16-9"

The answer in Java code

Possibility 1:

public class Answer {
  public static String findSquares(last int n) {
    last lengthy a = (n + 1) / 2;
    last lengthy b = a - 1;
    return String.format("%d-%d", a * a, b * b);
  }
}

Possibility 2:

interface Answer {
  static String findSquares(lengthy n) {
    return (n /= 2) * n + 2 * n + 1 + "-" + n * n;
  }
}

Possibility 3:

public class Answer{
  public static String findSquares(int n){
    lengthy n1 = n/2;
    lengthy n2 = n1+1;
    return String.valueOf(n2*n2)+"-"+ String.valueOf(n1*n1);
  }
}

Check circumstances to validate our answer

import org.junit.Check;
import static org.junit.Assert.assertEquals;
import org.junit.runners.JUnit4;

public class SolutionTest {
    @Check
    public void testBasicNumbers() {
        assertEquals("25-16",Answer.findSquares(9));
    }
    @Check
    public void testSmallerNumbers() {
        assertEquals("1-0",Answer.findSquares(1));
    }
    @Check
    public void testBiggerNumbers() {
        assertEquals("891136-889249",Answer.findSquares(1887));
        assertEquals("2499600016-2499500025",Answer.findSquares(99991));
    }
}