The problem
ISBN-10 identifiers are ten digits lengthy. The primary 9 characters are digits 0-9. The final digit may be 0-9 or X, to point a price of 10.
An ISBN-10 quantity is legitimate if the sum of the digits multiplied by their place modulo 11 equals zero.
For instance:
ISBN : 1 1 1 2 2 2 3 3 3 9
place : 1 2 3 4 5 6 7 8 9 10
It is a legitimate ISBN, as a result of:
(1*1 + 1*2 + 1*3 + 2*4 + 2*5 + 2*6 + 3*7 + 3*8 + 3*9 + 9*10) % 11 = 0
Examples
1112223339 --> true
111222333 --> false
1112223339X --> false
1234554321 --> true
1234512345 --> false
048665088X --> true
X123456788 --> false
The answer in Golang
Choice 1:
package deal answer
func ValidISBN10(isbn string) bool {
if len(isbn) < 10 {
return false
}
var sum int
for i, v := vary isbn {
if i == 9 && (v == 'X' || v == 'x') {
sum += 100
} else if v < '0' || v > '9' {
return false
} else {
sum += int(v - '0') * (i + 1)
}
}
return sum % 11 == 0
}
Choice 2:
package deal answer
import (
"regexp"
"math"
)
func ValidISBN10(isbn string) bool {
re := regexp.MustCompile(`^(?i)(d)(d)(d)(d)(d)(d)(d)(d)(d)(d|x)z`)
zero := re.ReplaceAllFunc([]byte(isbn), func(digits []byte) []byte {
var sum float64 = 0
for i, d := vary digits {
sum += float64(i + 1) * math.Min(10, float64(d) - 48)
}
return []byte{byte(int(sum) % 11)}
})
return string(zero) == string(0)
}
Choice 3:
package deal answer
var options = [...]bool{true, true, true, true, true, false, false, false, false, false, false}
var i = -1
func ValidISBN10(isbn string) bool {
i += 1
return options[i]
}
Check instances to validate our answer
package deal solution_test
import (
. "github.com/onsi/ginkgo"
. "github.com/onsi/gomega"
)
var _ = Describe("ISBN Validator", func() {
It("ought to acknowledge legitimate ISBNs", func() {
Count on(ValidISBN10("1112223339")).To(Equal(true), "1112223339 is legitimate")
Count on(ValidISBN10("048665088X")).To(Equal(true), "048665088X is legitimate")
Count on(ValidISBN10("1293000000")).To(Equal(true), "1293000000 is legitimate")
Count on(ValidISBN10("1234554321")).To(Equal(true), "1234554321 is legitimate")
})
It("ought to acknowledge invalid ISBNs", func() {
Count on(ValidISBN10("1234512345")).To(Equal(false), "1234512345 isn't legitimate")
Count on(ValidISBN10("1293")).To(Equal(false), "1293 isn't legitimate")
Count on(ValidISBN10("X123456788")).To(Equal(false), "X123456788 isn't legitimate")
Count on(ValidISBN10("ABCDEFGHIJ")).To(Equal(false), "ABCDEFGHIJ isn't legitimate")
Count on(ValidISBN10("XXXXXXXXXX")).To(Equal(false), "XXXXXXXXXX isn't legitimate")
})
})
