The problem
Full the sq. sum operate in order that it squares every quantity handed into it after which sums the outcomes collectively.
For instance, for [1, 2, 2] it ought to return 9 as a result of 1^2 + 2^2 + 2^2 = 9.
Full the sq. sum operate in order that it squares every quantity handed into it after which sums the outcomes collectively.
For instance, for [1, 2, 2] it ought to return 9 as a result of 1^2 + 2^2 + 2^2 = 9.
The answer in Python
Possibility 1:
def square_sum(numbers):
out = []
for i in numbers:
out.append(i**2)
return sum(out)
Possibility 2:
def square_sum(numbers):
return sum(x ** 2 for x in numbers)
Possibility 3:
def square_sum(numbers):
return sum(map(lambda x: x**2,numbers))
Check circumstances to validate our answer
import check
from answer import square_sum
@check.describe("Fastened Assessments")
def basic_tests():
@check.it('Fundamental Check Instances')
def basic_test_cases():
check.assert_equals(square_sum([1,2]), 5)
check.assert_equals(square_sum([0, 3, 4, 5]), 50)
check.assert_equals(square_sum([]), 0)
check.assert_equals(square_sum([-1,-2]), 5)
check.assert_equals(square_sum([-1,0,1]), 2)
